2cos^2(x)-3cos(x)+1=0

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Solution for 2cos^2(x)-3cos(x)+1=0 equation:


Simplifying
2cos2(x) + -3cos(x) + 1 = 0

Multiply cos2 * x
2cos2x + -3cos(x) + 1 = 0

Multiply cos * x
2cos2x + -3cosx + 1 = 0

Reorder the terms:
1 + -3cosx + 2cos2x = 0

Solving
1 + -3cosx + 2cos2x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -3cosx + -1 + 2cos2x = 0 + -1

Reorder the terms:
1 + -1 + -3cosx + 2cos2x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -3cosx + 2cos2x = 0 + -1
-3cosx + 2cos2x = 0 + -1

Combine like terms: 0 + -1 = -1
-3cosx + 2cos2x = -1

Reorder the terms:
1 + -3cosx + 2cos2x = -1 + 1

Combine like terms: -1 + 1 = 0
1 + -3cosx + 2cos2x = 0

The solution to this equation could not be determined.

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